Tuesday 6 November 2012

Fresher Off Campus For Engineering Graduates @ “CISCO”


About Company
Name: CISCO
Website: www.cisco.com
Job Details
Education: BE / B.Tech
Experience: Fresher – 2011/12
Location: Chennai
Walk-in On 18th Nov 2012 @ Chennai 
Job Description
Cisco Fresher Off Campus for 2011-2012 Batch Engineering Graduates
Eligibility:
Should have studied BE/B.TECH (Computer Science and Engg., Electronics and Comm. Engg., Electrical and Instrumentation Engg., Electricals and Electronics Engg. and Information Tech. only) / ME / MTech more than 70% aggregate marks or (equivalent scores) throughout in academics (ONLY 2011 & 2012 passed out candidates).
Should have 75% aggregate in 10th and 12th.
Mode of Education should be Full-time ONLY.
No Gap in academics.

How  To Apply:

Click here to register. Prior online registration is a must. Only registered candidates are permitted.
Once registered, have a print out of your hall ticket that will be issued to you after registration.
Please carry a copy of your resume.
The Room, Seating and the Time Slot will be communicated to you through the hall ticket.
Walk-in Address
Tagore Engineering college,
Rathinamangalam, Vandalur(via).
Chennai - 600 048.

Monday 5 November 2012

Valuelabs Question Paper(28/10/2012)



Test Pattern(25bits-40mins)

Section1
Arrangement of sentences(5ques-5marks)

Section 2
Paragraph Questions(5q-5m)

Section 3
General Knowledge(2q-2m)

Section 4
Arithmetic and Reasoning(8q-8m)

Section 5
Simple C programs(5q-5m)

Some questions
Q:In a Group15,7 have studied latin,8 have studied greek,and 3 have not studied either How many of them studied both latin and greek

Q:selling price is doubled profit is tripled then what is the profit percentage?
 Answer     Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x)    y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
 Profit % =xx 100% = 100%
x

Q:Who is the founder of Google
       Answer: Larry Page

Q:The 10th Biodeversity COP meeting is held at?
     Answer:Japan

Q:void main()
{
             int  const * p=5;
             printf("%d",++(*p));
}
Answer:
Compiler error: Cannot modify a constant value.
Explanation
p is a pointer to a "constant integer". But we tried to change the value of the "constant integer".

Q: main()
{
              int c[ ]={2.8,3.4,4,6.7,5};
              int j,*p=c,*q=c;
              for(j=0;j<5;j++) {
                          printf(" %d ",*c);
                          ++q;     }
              for(j=0;j<5;j++){
printf(" %d ",*p);
++p;      }
}
Answer:
            2 2 2 2 2 2 3 4 6 5
Explanation:
Initially pointer c is assigned to both p and q. In the first loop, since only q is incremented and not c , the value 2 will be printed 5 times. In second loop pitself is incremented. So the values 2 3 4 6 5 will be printed. 

Q: #define int char
main()
{
             int i=65;
             printf("sizeof(i)=%d",sizeof(i));
}
Answer:
                          sizeof(i)=1
Explanation:
Since the #define replaces the string  int by the macro char

Q: main()
{
printf("\nab");
printf("\bsi");
printf("\rha");
}
Answer:
hai
Explanation:
\n  - newline
\b  - backspace
\r  - linefeed

Q: enum colors {BLACK,BLUE,GREEN}
 main()
{
  
 printf("%d..%d..%d",BLACK,BLUE,GREEN);
   
 return(1);
}
Answer:
0..1..2
Explanation:
enum assigns numbers starting from 0, if not explicitly defined.